<PRE><B>Question 353815</B>
let rate of one car be xkph
other car rate will be x+24 kph
..
distance 702 from each other after 6 hours
since they are going away from each other the effective rate will be x+x+24 = 2x+24 kph
..
distance = rate * time
 702 = (2x+24) * 6
702/6 = 2x+24
117 =2x+24
117-24 = 2x
93=2x
x= 46.5 kph
other car rate = x+24 = 46.5 +24 = 70.5 kph
...
m.ananth@hotmail.ca
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