<PRE><B>Question 353799</B>
2 bad, 10 good eggs


No. of ways to choose 4 eggs from total 12 =  12C4

A.: 
  
       No. of ways to choose exactly one bad = 2C1 * 10C3 = 240 


        probability of exactly one bad =  240 / 495



B.:  No. of ways to choose all 4 good eggs = 10C4 = 210  

       probability of all eggs are good = 210/495

   so, now probability of at least one bad among 4 =  1 - 210/495


 = 285 /495  
        

           
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