Question 353772
x, x+2,x+4,x+6 be the numbers
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3/4 of the sum of second and fourth = 3/4 ( x+2+x+6)
sum of first & third = x+x+4
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3/4(2x+8)=2x+4
3(2x+8)=4(2x+4)
6x+24=8x+16
8x-6x=24-16
2x=8
x= 4...
numbers are 4,6,8,10
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