Question 353692
Let x = the first integer. Then
x+1 is the second and
x+2 is the third.
"4 times the third decreased by one half the second is 4" now translates into:
{{{4(x+2) - (1/2)(x+1) = 4}}}
Simplifying:
{{{4x+8 - (1/2)x -1/2 = 4}}}
Get rid of the fractions by multiplying both sides by 2:
{{{8x+16 - x -1 = 8}}}
{{{7x + 15 = 8}}}
Subtract 15 fom each side:
7x = -7
Divide both sides by 7:
x = -1
Since "x" was the first integer the others, x+1 and x+2, are 0 and 1