Question 353686
Let L = length and W = width.
"The length is 8m more than twice the width" translates into:
L = 8 + 2W
From the information on the perimeter we also know that
160 = 2L + 2W<br>
We can solve this system in several ways. Since the first equation is already soved for L, I will use the Substitution Method and substitute for L in the second equation:
160 = 2(8 + 2W) + 2W
Simplify:
160 = 16 + 4W + 2W
160 = 16 + 6W
Subtract 16 from each side:
144 = 6W
Divide both sides by 6:
24 = W
With L = 8 + 2W we can find L:
L = 8 + 2(24)
L = 8 + 48
L = 56<br>
To check you can make sure that with a length of 56 and a width of 24 the...
- the perimeter is 160, and
- the length is 8 more that twice the width.
This answer checks.