Question 353657
In other words,what is x so that 
{{{6^x=sqrt(6)}}}
{{{highlight(x=1/2)}}}
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or
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{{{log(6,(sqrt(6)))=(1/2)log(6,(6))}}}
{{{log(6,(sqrt(6)))=(1/2)*1}}}
{{{log(6,(sqrt(6)))=highlight((1/2))}}}