Question 353626
Here are the probabilities for each number of heads.
{{{P(0)=1*(0.5)^(7-0)*(0.5)^0}}}
{{{P(1)=7*(0.5)^(7-1)*(0.5)^1}}}
{{{P(2)=21*(0.5)^(7-2)*(0.5)^2}}}
{{{P(3)=35*(0.5)^(7-3)*(0.5)^3}}}
{{{P(4)=35*(0.5)^(7-4)*(0.5)^4}}}
{{{P(5)=21*(0.5)^(7-5)*(0.5)^5}}}
{{{P(6)=7*(0.5)^(7-6)*(0.5)^6=0.0546875}}}
{{{P(7)=1*(0.5)^(7-7)*(0.5)^7=0.0078125}}}
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P(6 or 7)={{{P(6)+P(7)=0.0625}}}