Question 353627
x+y=4
xy=-32
from the first equation x=4-y, plug that into second one
{{{(4-y)y=-32}}}
{{{4y-y^2=-32}}}
{{{0=y^2-4y-32}}} factor
{{{0=(y-8)(y+4)}}}
so y is 8 or y is -4, now you plug those into x=4-y and solve for x
x=4-8=-4    or x=4-(-4)=8
so looks lie the answer is (-4, 8) or (8, -4). Either way, the numbers are -4 and 8.