Question 353609
2x+3y=5
3x-2y=1
Lets mulitply the first equation by 2 and second one by 3 and then add them together.

{{{
4x+6y=10 }}}
{{{9x-6y=3
}}} When we add them we get
{{{
13x=13
}}} divide both sides by 13 and we get
{{{x=1}}} Now we can plug that into either of the original equations and solve for y. I will plug it in the first equation.

{{{2*1+3y=5}}}
{{{2+3y=5}}} subtract 2 from each side and you get
{{{3y=3}}} divide both sides by 3 and you get
{{{y=1}}} So the answer is (1,1)