Question 353366
Perpendicular lines have slopes that are negative reciprocals,
{{{m1*m2=-1}}}
{{{-2*m2=-1}}}
{{{m2=1/2}}}
Now use the point slope form of a line, {{{y=yp=m(x-xp)}}}
{{{y-7=(1/2)(x-(-4))}}}
{{{y-7=(1/2)x+2}}}
{{{highlight(y=(1/2)x+9)}}}
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{{{drawing(300,300,-10,6,-6,10,circle(-4,7,0.3),grid(1),graph(300,300,-10,6,-6,10,-2x+6,(1/2)x+9))}}}