Question 353582
Use the chain rule,
Let {{{u=sin(pi*x)}}}
{{{dy/dx=(dy/du)*(du/dx)}}}
{{{dy/du=ln(2)*2^u}}}
{{{du/dx=cos(pi*x)*pi}}}
Put it all together,
{{{dy/dx=ln(2)*2^(u)*pi*cos(pi*x)}}}
{{{dy/dx=ln(2)*pi*2^(sin(pi*x))*cos(pi*x)}}}