<PRE><B>Question 353272</B>
How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution?
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Equation:
alcohol + alcohol = alcohol
0.50*20 + 0.14x = 0.30(20+x)
Multiply thru by 100 to get:
50*20 + 14x = 30*20 + 30x
16x = 20*20
x = 25 L (amt. of 14% solution needed for the mixture)
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Cheers,
Stan H.</PRE>