Question 353233
Hi,
log(base 4)(x-9)=2

*[tex \large\ \  y = \log_b(x) \ \ \Rightarrow\ \ b^y = x]
{{{4^2 = x - 9}}}
x = 25
.
log(base 4)z + log(base 4)(z-3)=1
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
.
*[tex \large\ \log_b(z(z-3)= 1]
{{{4^1 = z(z-3))}}}
{{{z^2 - 3z -  4 = 0}}}
(z - 4)(z + 1) = 0
.
z = -1 & 4