Question 352991

For first set 4 applications can be selected from 20  by  20C4 ways

   
  For second set 4 applications can be selected from 16 by  16C4 ways


For third set 4 applications can be selected from 12 by  12C4 ways 


For fourth set 4 applications can be selected from 8 by  8C4 ways


For fifth set 4 applications can be selected from 4 by  4C4 ways





Hence total no. of ways = 20C4 * 16C4 * 12C4 * 8C4 * 4C4

           
= 20! / (4^5)