Question 353039
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For the general quadratic function:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p(x)\ =\ ax^2\ +\ bx +\ c]


the coordinates of the vertex are:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x_v = \frac{-b}{2a}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y_v = p(x_v) = p\left(\frac{-b}{2a}\right)]


The equation of the line of symmetry is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ x_v]


The maximum or minimum of *[tex \Large p(x)] is the function value at the vertex, that is, *[tex \Large y_v].  If the lead coefficient of *[tex \Large p(x)] is positive, the graph opens upward and the vertex is a minimum.  If negative, the graph opens downward and the vertex is a maximum.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{19}{2}] is the maximum value of the function.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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