Question 353035
f(x)=8-x^2 
I got 
Vertex ?
Vertex occurs when x = -b/(2a) = -0/(2*-1) = 0
f(0) = 8
Vertex is (0,8)
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Line of Symmetry x=0
Max/Min:: Max because the coefficient of x^2 is negative
Value of, f(0)=8 max
how do I graph this one?
Plot (0,8) and a couple points to the left and to 
the right of x = 0
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{{{graph(400,300,-10,10,-10,10,8-x^2)}}}
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Cheers,
Stan H.