Question 39684
Use this as an example:
{{{0 = x^2 - 6x + 9}}} original
{{{-9 = x^2 - 6x}}} only group the {{{x}}}'s
{{{-9 + 9 = (x - 3)^2}}} set it up as {{{x}}} minus half of the {{{-6}}} squared
and add {{{-3}}} squared to the other side
{{{0 = (x - 3)^2}}}
This means:
{{{0 = (x - 3)(x - 3)}}}
Zero times any number is .... zero!! Set each set equal to zero; since you have a double root, you only need to set one section to zero.
{{{x - 3 = 0}}}
{{{x = 3}}} Your only answer is three.