Question 352948
I'm assuming that the equation is {{{y=(x-2)^2}}}



{{{y=(x-2)^2}}} Start with the given equation.



{{{x=(y-2)^2}}} Swap x and y. The goal now is to solve for y.



{{{sqrt(x)=y-2}}} Take the square root of both sides.



{{{sqrt(x)+2=y}}} Add 2 to both sides.



{{{y=sqrt(x)+2}}} Flip the equation.



So the inverse is *[Tex \LARGE f^{-1}(x)=\sqrt{x}+2] assuming that {{{x>=2}}}



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