Question 352819
let x=one number
let y=the other number
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you are given:  One number is 2 more than 5 times another
x=2+5y
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also you are told: Their product is 24
x*y=24
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substitute x=2+5y into x*y=24 in order to reduce the problem by one variable
x*y=(2+5y)*y=24
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{{{2y+5y^2=24 }}}  
{{{5y^2+2y-24=0}}}
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use the quadratic formula to solve for y
where a=5, b=2 and c=-24
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y={{{(-2-Sqrt((-2)^2-4*5*(-24)))/(2*5)}}}  or {{{y=(-2+Sqrt((-2)^2-4*5*(-24)))/(2*5)}}}
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y=(-2-22)/10=-2.4  or y=(-2+22)/10=2
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substitute y=-2.4 or y=2 into x=2+5y to find x
x=2+5(-2.4)=-10 and x=2+5*(2)=12
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so the possible answers are x=-10 and y=-2.4 or x=12 and y=2