Question 352743
let first integer be x
than the second one is x+5
{{{4(x+5)=6+6x}}}
{{{4x+20=6+6x}}} subtract 4x from each side
{{{20=6+2x}}} subtract 6 from each side

{{{14=2x}}} divide both sides by 2
{{{7=x}}} so the smaller number is 7 and the bigger number is 7+5=12