Question 352681
Hi,
*Note: slope intercept form of a line is y = mx + b where ma is the slope and b is the y-intercept (value of y where the line passes thru the y-axis)
.
y = (-5/3)x + b
.
Sustituting P(6,1)
1 = -10 + b
11 = b   
Pt(0,11) is a point on the line.
.
y = (-5/3)x + 11 


{{{drawing(300,300,-12,12, 
-12,12,grid(1),
circle(6, 1,0.2),
circle(0, 11,0.3),

graph(300,300,-12,12,-12,12,(-5/3)x + 11))}}}