Question 352607
Find the vertex, the line of symmetry, the maxiumum or minimum value of the quadratic function, and graph the function.
f(x)=-2x^2+2x+3
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vertex occurs at x = -b/(2a) = -2/(2*-2) = 1/4
This is a maximum
The x-coordinate of the vertex is:1/4
The y-coordinate of the vertex is:f(1/4) = 3.375
The equation of the line of symmetry is x= 1/4
The maximum/minimum of f(x) is: max = 3.375
The value, f(1/4)=3.375 is maximum because the coefficient of x^2 is negative. 
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{{{graph(400,300,-10,10,-10,10,-2x^2+2x+3)}}}
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Cheers,
Stan H.