Question 352472
Let {{{a}}} = price/100 grams ham
Let {{{b}}} = price/100 grams turkey breast
Let {{{c}}} = price/100 grams chicken breast 
given:
(1) {{{3a + 2b = 890}}} (in cents)
(2) {{{1a + 3c = 900}}}
(3) {{{2b + 2c = 940}}}
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There are 3 equations and 3 unknowns, so
it's solvable
Subtract (1) from (3)
(3) {{{2b + 2c = 940}}}
(1) {{{-3a - 2b = -890}}}
{{{2c - 3a = 50}}}
{{{2c = 3a + 50}}}
{{{c = (1/2)*(3a + 50)}}}
Substitute this in (2) 
{{{a + (3/2)*(3a + 50) = 900}}}
{{{2a + 9a + 150 = 1800}}}
{{{11a = 1650}}}
{{{a = 150}}}
Substitute this in (2)
(2) {{{1a + 3c = 900}}}
{{{150 + 3c = 900}}}
{{{3c = 750}}}
{{{c = 250}}}
Substitute in (3)
(3) {{{2b + 2*250 = 940}}}
{{{2b = 940 - 500}}}
{{{2b = 440}}}
{{{b = 220}}}
$1.50 = price/100 grams ham
$2.20 = price/100 grams turkey breast
$2.50 = price/100 grams chicken breast