Question 39746
Starting with the "point-slope" form: {{{y = mx + b}}}, you'll need to find the slope, m, of the line that passes through the points (1, 5) and (0, 0).

The slope of a line is given by:
{{{m = (y2-y1)/(x2-x1)}}} Where: (x1, y1) is (1, 5) and (x2, y2) is (0, 0), so substituting these values into the slope formula, you get:
{{{m = (0-5)/(0-1)}}}
{{{m = (-5)/-1}}}
{{{m = 5}}} Now you substitute this value of m into the point-slope form.

{{{y = 5x + b}}} Next, you will substitute the x and y values from either one of the two given points and solve for b, the y-intercept.
Choosing the first point (1, 5), you'll get:

{{{5 = 5(1) + b}}} Simplify and solve for b. Subtract 5 from both sides of the equation.
{{{b = 0}}}
Now you can write the final equation in the point-slope form:

{{{y = 5x}}} Since b = 0, you won't need to put it in the equation.