Question 352255
{{{sqrt(8+2)sqrt(15)}}}
{{{sqrt(10)sqrt(15)}}} put everything under the same radical
{{{sqrt(10*15)}}} combine
{{{sqrt(150)}}} now break it out again but with different factors, the ones we can take square root of
{{{sqrt(25*6)}}}
{{{sqrt(25)sqrt(6)}}}
{{{5sqrt(6)}}}