Question 352236
If you want to find the equation of line with a given a slope of {{{2}}} which goes through the point (0,1), you can simply use the point-slope formula to find the equation:



---Point-Slope Formula---
{{{y-y[1]=m(x-x[1])}}} where {{{m}}} is the slope, and *[Tex \Large \left(x_{1},y_{1}\right)] is the given point


So lets use the Point-Slope Formula to find the equation of the line


{{{y-1=(2)(x-0)}}} Plug in {{{m=2}}}, {{{x[1]=0}}}, and {{{y[1]=1}}} (these values are given)



{{{y-1=2x+(2)(0)}}} Distribute {{{2}}}



{{{y-1=2x+0}}} Multiply {{{2}}} and {{{0}}} to get {{{0}}}



{{{y=2x+0+1}}} Add 1 to  both sides to isolate y



{{{y=2x+1}}} Combine like terms {{{0}}} and {{{1}}} to get {{{1}}} 


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Answer:



So the equation of the line with a slope of {{{2}}} which goes through the point (0,1) is {{{y=2x+1}}}