Question 352189
Hi,
*Note: The probability of x successes in n trials is: 
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P = nCx* {{{p^x}}}*{{{q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
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nCx = {{{n!/(x!(n-x)!)}}}
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Question states p(dog drawn) = 10/25 0r .4  and q (cat drawn) = .6
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Probability (3 dogs and 4 cats) 

7C3 = {{{ 7!/(3!*4!)!= 35 }}}
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P((3 dogs and 4 cats) = {{{35*(.4)^3*(.6)^4}}} = .29
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