Question 352181
The perimeter of a basketball court is 108 meters. The length is 6 meters longer than twice the width. Find the length and width.

So we know that {{{P=2(l+w)}}} where
P-perimeter
l-length
w-width
 
Let the width be w, then the length is 2w+6. Now we plug those sides and the perimeter into our formula.
{{{108=2*(w+2*w+6)}}} now you simplify and solve for w.
{{{108=2*(3*w+6)}}} divide each side by 2, and you get
{{{54=3*w+6}}}  now subtract 6 from each side, and you get
{{{48=3*w}}} now divide each side by 3, and you get
{{{16=w}}}  
So the width is 16 meters then the length is {{{2*w+6=2*16+6=32+6=38}}} meters.