Question 352121
{{{f=(x^2y^3)/z=x^2y^3z^(-1)}}}
Remember treat the other variables as constant while differentiating with respect to one variable.
{{{fx=2xy^3z^(-1)=(2xy^3)/z}}}
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{{{fy=3x^2y^2z^(-1)=(3x^2y^2)/z}}}
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{{{fz=-x^2y^3z^(-2)=-(x^2y^3)/z^2}}}