Question 351732
Hi,
*Note paralel lines have the same slop

.Using the point-slope form
{{{m =(y[2] - y[1])/(x[2] - x[1])}}}
.
finding the slope 
(-1,4) and (2,-3),
{{{m =((-3) - 4)/(2 - (-1))}}}
.
m = -7/3 (the slope of both lines) As the slope is negative, we know the line(s) slope to the left
.
Using the standard slope-intercept form y = mx + b where m is the slope and  b is the y- intercept(the value of y when the line passes thru the y-axis)
.
for the New line
y = (-7/3)x + b
.
Substituting Pt(4,-2) to solve for b
-2 = -28/3 + b
-6/3 + 28/3 = b
22/3 = b
.
New line is:
y =  (-7/3)x + 22/3
.
Standar form would be
3y + 7x = 22