Question 351715


{{{3x-8y=4}}} Start with the given equation.



{{{-8y=4-3x}}} Subtract {{{3x}}} from both sides.



{{{-8y=-3x+4}}} Rearrange the terms.



{{{y=(-3x+4)/(-8)}}} Divide both sides by {{{-8}}} to isolate y.



{{{y=((-3)/(-8))x+(4)/(-8)}}} Break up the fraction.



{{{y=(3/8)x-1/2}}} Reduce.



So the equation {{{y=(3/8)x-1/2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=3/8}}} and the y-intercept is {{{b=-1/2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{1}{2}\right)]