Question 351626
{{{(32x^2y-48xy^2+8x)/(4x)=(32x^2y)/(4x)+(-48xy^2)/(4x)+(8x)/(4x)}}}
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{{{(32x^2y-48xy^2+8x)/(4x)=(32/4)x^(2-1)y+(-48/4)x^(1-1)y^2)+(8/4)x^(1-1)}}}
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{{{(32x^2y-48xy^2+8x)/(4x)=(8)x^(1)y+(-12)x^(0)y^2+(2)x^(0)}}}
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{{{(32x^2y-48xy^2+8x)/(4x)=highlight(8xy-12y^2+2)}}}