Question 351689
{{{17^(5x) = 5*6^x}}}
{{{log(17,(5x))=log(17,(5*6^x))}}}
{{{5x=log(17,(5))+log(17,(6^x)))}}}
{{{5x=log(17,(5))+x*log(17,(6)))}}}
{{{5x-x*log(17,(6))=log(17,(5))}}}
{{{x(5-log(17,(6)))=log(17,(5))}}}
{{{highlight(x=log(17,(5))/(5-log(17,(6))))}}}
or approximately,
{{{x=0.13}}}