<PRE><B>Question 351658</B>
Hi
*note: one way would be using cramers rule to solve this system of equations: which is eliminating one the of the variables by adding the two equations together.

1/x+1/y=8
3/x-5/y=0
.
first you would need to multiply @ term in the first equation by 5
{{{(5*1/x)+(5*1/y)= 40}}}
{{{(3/x)-(5/y)= 0}}}
.
{{{(5/x)+(5/y)= 40}}}
{{{(3/x)-(5/y)= 0}}}
.
8/x = 40
8 = 40*x
x = 8/40 = 1/5
.
Substitute x to solve for y;
3/x-5/y=0
15 = 5/y
y = 5/15 = 1/3</PRE>