Question 351645
Hi,
Note: n represents the positioning of the terms in the series.
If I am understanding the question properly:
{{{(n/2)*((-1)^n + 1))}}}
.

n=1 
{{{(1/2)*((-1)^1 + 1))}}} = 0
.
n=2
{{{(2/2)*((-1)^2 + 1))}}} = 2
.
n=3
{{{(3/2)*((-1)^3 + 1))}}} = 0
etc