<PRE><B>Question 351649</B>
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Add -2x to 3x in the LHS giving you


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ x]


But


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ \equiv\ x\ \forall\ x\ \in\ \mathbb{R}]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \mathbb{Z}\ \subset\ \mathbb{R}].


Therefore


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -2x\ +\ 3x\ \equiv\ x\ \forall\ x\ \in\ \mathbb{Z}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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