Question 351447
{{{N+D+Q=24}}}
.
.
.
{{{N=2Q}}}
{{{D=3Q}}}
Substitute into the first equation,
{{{2Q+3Q+Q=24}}}
{{{6Q=24}}}
{{{highlight(Q=4)}}}
Then,
{{{N=2(4)}}}
{{{highlight(N=8)}}}
and,
{{{D=3(4)}}}
{{{highlight(D=12)}}}
Eight nickels, twelve dimes, and eight quarters.