Question 351462
Let {{{N}}}, {{{N+2}}}, {{{N+4}}}, and {{{N+6}}} be the consecutive even integers.
{{{3N=10+2*(N+6)}}}
{{{3N=10+2N+12}}}
{{{3N=2N+22}}}
{{{N=22}}}
The integers are 22,24,26,and 28.