Question 351417
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SOHCAHTOA
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{{{tan(x)=(opposite/adjacent)}}}
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If you recall the unit circle, you know that the sin of something is essentially the 'y' component.  The 'y' component is basically the opposite side.
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If you recall the unit circle again, you know that the cos of something is essentially the 'x' component.  The 'x' component is basically the adjacent side.
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Therefore, if {{{tan(x)=(opposite/adjacent)}}}, then {{{tan(x)=(sin(x)/cos(x))}}}
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Since you have the tangent, {{{4/5}}}, you can easily see that {{{sin(x)=4}}} and {{{cos(x)=5}}}