Question 351154
Problem 1. The sum of the digits of a two-digit number is 14. If the digits are reversed, the number is increased by 18. What is the number?
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Let the number be 10t+u
The reversed number is 10u+t
Equations:
t + u = 14
10u+t - (10t+u) = 18
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Simplify the 2nd equation 
t + u = 14
u - t = 2
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Add to get 2u = 16
u = 8
Then t = 6
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1st number: 68

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Problem 2. One number is less than another number. The sum of the two numbers is four times their difference. What are the numbers?
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Not enough information.
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Cheers,
Stan H.