Question 351127
A line goes through the point (4,-3) and has a slope of -3/2.  Graph this line.
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The equation can be found by plugging the given info into the "point-slope" form:
y - y1 = m(x - x1)
y - (-3) = (-3/2)(x - 4)
y + 3 = (-3/2)x + 6
y = (-3/2)x + 3
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*[invoke describe_linear_equation 3/2, 1, 3 ]