<PRE><B>Question 351103</B>
Hi,
*Note: distance to and from the same.  D = r*t
Let r be the speed and t the time it takes to travel to its destination
Return speed is then 2*r and the time left for that trip is (5-t)
.
Question states:
going to destination
r*t = 120km
r = 120km/t
.
returning from destination (substitute and solve for t
{{{(240/t)(5-t)= 120}}}
.
simplify and solve:
240(5-t) = 120t
1200 - 240t = 120t
1200 = 360t
3 1/3 hr = t
.
Finding rate going to destination
r*(10/3)= 120
r = 36 mi/hr</PRE>