Question 39666
You are correct as far as you have gone.
{{{log(125x^3)+log(16x^4) = 3}}} Now apply the "product rule" for logarthms:{{{log(M)+log(N) = logMN}}}
{{{log((125x^3)(16x^4)) = 3}}} Simplify.
{{{log(2000x^7) = 3}}} Convert to exponential form.
{{{10^3 = 2000x^7}}} Divide both sides by 2000.
{{{1/2 = x^7}}}
{{{x = 0.9057}}}Approximately.