<PRE><B>Question 350938</B>
A right triangle has a hypoteneuse 11cm long. If the perimeter of the traingle is 25cm, find the lengths of the two other sides.

Let a and b be the lengths of the other two sides. By the Pythagorean Theorem we have:

1.) 11^2 = a^2 + b^2

Since the perimeter is 25 we also know a + b + 11 = 25 so:

a = 25 - 11 - b or
a = 14 - b

Substituting 14-b for a in 1.) we have:

121 = (14-b)^2 + b^2

121 = 14^2 - 28*b + b^2 + b^2

121 = 196 - 26*b^2
26*b^2 = 75
b^2 = 75/26
b = sqrt(75/26)
a = 14 - sqrt(75/26)



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