<PRE><B>Question 351006</B>
One third the product of two consecutive odd integers is 65. Find the integers? 
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1st: 2x-1
2nd: 2x+1
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Equation:
(1/3)[(2x-1)(2x+1)] = 65
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Multiply both sides by 3
4x^2-1 = 195
4x^2 = 196
x^2 = 49
x = 7 or x = -7
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If x = 7:
1st: 2x-1 = 13
2nd: 2x+1 = 15
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If x = -7:
1st: 2x-1 = -15
2nd: 2x+1 = -13
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Cheers,
Stan H.</PRE>