Question 349036
There are 8 tasks and 4 employee, according to question each one get at least 1 or almost 3 task 
so possible conditions are  (2, 2 , 2, 2), (3,1,1,3)and (1,3,2,2)
                     
case 1: when each will get 2 tasks...
         no. of ways = 8C2 * 6C2 * 4C2 * 2C2 = 28*15* 6*1 = 2520 



case 2: when two have 3 task and two have 1 task
         it can be arrange in  4!/ {2!*2!) = 6 ways 
                like 1133,3311,......
      
      no. of ways = 6 * [ 8C3 * 5C3 * 2C1 * 1C1 ]= 6 * 56*10 *2*1 = 6720


 
case 3: when one have 3, one have 1 and two have 2 tasks..
         it can be arrange in 4!/2! = 12 ways
               
  no. of ways = 12 * [ 8C3 * 5C2 * 3C2 * 1C1 ] = 12 * 56 * 10 * 3 *1 =20160


         
          total no. of ways = 2520 + 6720 + 20160 = 29400