Question 349633

There are 5 women and 6 men. We have to select 2 women and 3 men. 

First case: both brothers are in committee
as both are in committee, now we have to choose 1 from remaining 4 men                
no. of ways = 5C2 * 4C1 = 10 * 4 = 40

Second case : both are not in committee
              now we have to choose all 3 men from remaining 4  

      no. of ways = 5C2 * 4C3 = 10 * 4 = 40

    total no. of ways = 40 + 40 = 80 

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