Question 350815
Let the numbers are x and y, their sum =(x+y) , difference =(x -y)

according to question.   
         2(x+y) = 3(x-y) + 8 .....(1)
    and  (x+y)/2 = (x-y) + 1 ....... (2)
  using (1) we got  -x +5y =8
   using (2) we got -x +3y =2

     now, we solve these two equations...
         subtract second equation from first....
               2y =6, y =3
           using first  -x + 5*3 = 8
                       => -x = 8-15 
                        => -x = -7
                        => x = 7

 so, numbers are 7 and 8