Question 350758
The length of a rectangle is five times its width. 
If the area of the rectangle is 405ft, find its perimeter.
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L = 5W
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Equation:
Area = LW
405 = (5W)W
81= W^2
W = 9
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L = 5W = 45
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Perimeter = 2(L+W)
P = 2(45+9)
P = 2(54)
P = 108
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Cheers,
Stan H.