<PRE><B>Question 350632</B>
Hi,
Let x represent the smaller number.  Then (x+4) will be the other.
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Question states
{{{x^2 + (x+4)^2 = 80}}}
.
{{{x^2 + x^2+ 8x +16 = 80}}}
.
{{{2x^2 + 8x +16 = 80}}}
.
{{{2x^2 + 8x -64 = 0}}}
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factor
(2x - 8)(x+8) = 0
(x+8) = 0  this solution will not result in a positive number
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(2x-8) = 0
x = 4
Numbers are 4 and 8
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check your answer
16 + 64 = 80</PRE>